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Question

Physics Question on Current electricity

In the circuit, the potential difference across PQPQ will be nearest to

A

9.6 V

B

6.6 V

C

4.8 V

D

3.2 V

Answer

3.2 V

Explanation

Solution

Potential difference across PQPQ i.e., potential difference across the resistance of 20Ω20 \,\Omega which is V=i×20V = i \times 20
i=48100+100+80+20i =\frac{48}{100+100+80+20}
=0.16A=0.16\, A
V=0.16×20=3.2VV =0.16 \times 20=3.2\, V