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Question: In the circuit shown, the coil has inductance and resistance. When X is joined to Y, the time consta...

In the circuit shown, the coil has inductance and resistance. When X is joined to Y, the time constant is t during growth of current. When the steady state is reached, rate of production of heat in the coil is "P" joule/sec. X is now joined to Z, and after long time of joining X to Z –

A

The total heat produced in the coil is Pt

B

The total heat produced in the coil is 12\frac{1}{2} Pt

C

The total heat produced in the coil is 2Pt

D

The data given is not sufficient to reach a conclusion

Answer

The total heat produced in the coil is 12\frac{1}{2} Pt

Explanation

Solution

Let L and R be the inductance and the resistance of the coil respectively

Let E = e.m.f. of the cell.

t = Time constant, I0 = E/R

P = I02I_{0}^{2}R = E2R\frac{E^{2}}{R}

Energy stored in the coil = 12\frac{1}{2} LI02LI_{0}^{2} = 12\frac{1}{2} L (E2R2)\left( \frac{E^{2}}{R^{2}} \right) = 12\frac{1}{2}

(LR)\left( \frac{L}{R} \right) (E2R)\left( \frac{E^{2}}{R} \right) = 12\frac{1}{2} tP

= total heat produced in the coil