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Question

Physics Question on Current electricity

In the circuit shown the cells A and B have negligible resistances. For VA=12V,R1=500ΩV_A =12\, V,\, R_1 =500\, \Omega and R=100ΩR =100\, \Omega the galvanometer (G) shows no deflection. The value of VBV_B is

A

4 V

B

2 V

C

12 V

D

6V

Answer

2 V

Explanation

Solution

Since the galvanometer shows no deflection so current will flow as shown in the figure.

Current, I=VAR1+R=12V(500+100)Ω=12600AI = \frac{V_A}{R_1+R} = \frac{12\, V}{(500+100)\,\Omega}=\frac{12}{600}\, A
VB=IR=(12600A)(100Ω)=2VV_B=IR=\bigg( \frac{12}{600}A\bigg) (100\, \Omega)=2\, V