Question

In the circuit shown in the given figure, the resistances $2\Omega,4\Omega$and $5\Omega$ are respectively

• A. 14 $T_{1}$and 40 $T_{2}$
• B. 40 $T_{1} > T_{2}$ and 14$T_{1} < T_{2}$
• C. 40 $T_{1} = T_{2}$ and 30$T_{1} = \frac{1}{T_{2}}$
• D. 14$7.5 \times 10^{- 4}ms^{- 1}$ and 30 $3 \times 10^{- 10}Vm^{- 1}$

Answer 1

Answer: (A)

14 $T_{1}$and 40 $T_{2}$

Answer 2

: Potential difference across $20\Omega = 20 \times 1$

= 20 V = potential difference across $R_{2}$

Current is $R_{2} = 0.5A$

$\therefore R_{2} = R_{2} = \frac{20.V}{0.5A} = 40\Omega.$

Potential difference across

$R_{1} = 69V - 20V = 49V.$

Current in $R_{1} = 0.5A + \frac{20}{10} + 1A = 3.5A$

$\therefore R_{1} = \frac{49}{3.5} = 14\Omega$