In the circuit shown in the given figure, the resistances (R... | Physics | SolveeIt

Question

In the circuit shown in the given figure, the resistances $R_1$ and $R_2$ are respectively

$\({14 \,\Omega}$ ) and $\({40 \,\Omega}$ )

$\({40 \,\Omega}$ ) and $\({14 \,\Omega}$ )

$\({40 \,\Omega}$ ) and $\({30 \,\Omega}$ )

$\({14 \,\Omega}$ ) and $\({30 \,\Omega}$ )

Answer

${14 \,\Omega}$ and ${40 \,\Omega}$

Explanation

Solution

Potential difference across $\({ 20 \,\Omega} = 20 \times 1$ ) $\(= {20 \, V}$ ) = potential difference across $\(R_2$ ) Current in $\(R_2 = 0.5 \, A$ ) $\(\therefore \:\: R_{2 } = \frac{20 V}{0.5 A} = 40 \Omega$ ) Potential difference across $\(R_1 = {69 \, V - 20 \, V}$ ) $\(={49 \, V}$ ) Current in $\(R_1 = 0.5 {A + \frac{20}{10} A + \, A = 3.5 \, A}$ ) $\(\therefore \:\:\: R_1 = \frac{49}{3.5} = 14 \, \Omega$ )

Physics Question on Current electricity

Solution