Question
Physics Question on Gravitation
In the circuit shown in the figure, the input voltage Vi is 20 V, VBE=0 and VCE=0. The values of IB,IC and β are given by:
A
(A) IB=20μA,IC=5 mA,β=250
B
(B) IB=40μA,IC=10 mA,β=250
C
(C) IB=40μA,IC=5 mA,β=125
D
(D) IB=25μA,IC=5 mA,β=200
Answer
(C) IB=40μA,IC=5 mA,β=125
Explanation
Solution
Explanation:
Given,Vi=VBE+RBiB....(1)20=500×103×iBiB=40μAV0=VCE−RCiC...(2)20=4×103iCiC=5 mAβ=ICIB=5 mA40μA=125Hence, the correct option is (C).