Question

In the circuit shown in the figure, find the current in $45\,\Omega$

• A. 4 A
• B. 2.5 A
• C. 2 A
• D. None of there

Answer 1

Answer: (C)

2 A

Answer 2

Since the two resistors are connected in series, the equivalent resistance is 1000Ω. Since this 100Ω and 100Ω are currently parallel, the equivalent will be 50Ω.

Now when 100Ω and 100Ω are arranged in sequence, the equivalent is 200Ω. Now that this 200Ω and 50Ω are parallel, the equivalent is 40Ω.

Since this 40Ω and 50Ω are now in series, the result of adding them up is 90Ω.

Now that 90Ω and 45Ω are parallel in the upper right corner, 90Ω will equal 45Ω.

Now, 90Ω, 90Ω, and 90Ω will equal 90Ω.

So by relation V=IR

Current will be 2 Ampere.

And Current in 45Ω will be 2 Ampere.

The relationship between current (I), voltage (V), and resistance (R) in an electrical circuit is established by the formula known as Ohm's Law. Georg Simon Ohm developed Ohm's law through an experiment in 1826. He noticed that if the temperature is constant, the current flowing through a circuit is exactly proportional to the voltage and inversely proportional to the resistance.

According to Ohm's rule, assuming all physical parameters, particularly temperature, stay constant, the potential difference at the ends of a conductor is precisely proportional to the current flowing through the conductor.

V ∝ I

When any two values of voltage, current, or resistance are known, the formula for Ohm's Law, Voltage (V) = Current (I) Resistance (R), aids in determining the value of the third variable that is lacking.

Calculating a component's power, current, efficiency, voltage, and resistance is one of the most fundamental electrical rules.

Ohm's law is applied in everyday life in electrical fuses that control current to safeguard circuits or in fans that control speed by altering resistance.