Question

In the circuit shown in the figure, C = 6mF. The charge stored in the capacitor of capacity C is-

• A. Zero
• B. 90 mC
• C. 40 mC
• D. 60 mC

Answer 1

Answer: (C)

40 mC

Answer 2

A to B KVL

10 –̃ 10 =

q = $\frac { 20 \mathrm { C } } { 3 }$ = $\frac { 20 } { 3 }$ × 6 mC ̃ q = 40mC