Question

In the circuit shown in the figure below the cells E₁ and E₂ have e.m.f. 4V and 8 V and internal resistance 0.5 ohm and 1.0 ohm respectively. Then the potential difference across cell E₁ and E₂ will be-

• A. 3.75 V, 7.5 V
• B. 4.25 V, 7.5 V
• C. 3.75 V, 3.75 V
• D. 4.25 V, 4.25 V

Answer 1

Answer: (B)

4.25 V, 7.5 V

Answer 2

I = $\frac{8–4}{8}$ = 0.5 A

V_8V = E – Ir = 8 – (0.5) (1) = 7.5 V

V_4V = E + Ir = 4 + (0.5) (0.5) = 4.25 V