Question

In the circuit shown in figure, with steady calculate current i in the adjoining circuit -current, the potential drop across the capacitor must be

• A. V
• B. $\frac{V}{2}$
• C. $\frac{V}{3}$
• D. $\frac{2V}{3}$

Answer 1

Answer: (C)

$\frac{V}{3}$

Answer 2

First convert two parallel cells into one cell.

⇒

Q $V_{\frac{2R}{3}} = 0$

∴ V_C = V/3

nductor as oven circuit)