Solveeit Logo

Question

Question: In the circuit shown in Figure, the p.d.s across the various elements are shown. What is the magnitu...

In the circuit shown in Figure, the p.d.s across the various elements are shown. What is the magnitude of the applied voltage?

Explanation

Solution

Hint : Magnitude is defined as 'distance or quantity' in basic terms. It represents the actual or relative scale or direction in which an object travels in the sense of motion.
We have to find the magnitude of applied voltage in the given circuit by using the values of the rms voltage measured across the resistor RR , the rms voltage measured across the inductor LL , and the rms voltage measured across the capacitor CC .
Vnet=VR2+(VLVC)2{V_{net}} = \sqrt {V_R^2 + {{\left( {{V_L} - {V_C}} \right)}^2}}

Complete Step By Step Answer:
Using the above formula, we can find the magnitude of applied voltage in the given circuit.
Vnet=VR2+(VLVC)2{V_{net}} = \sqrt {V_R^2 + {{\left( {{V_L} - {V_C}} \right)}^2}}
Where, Vnet{V_{net}} represents the magnitude of the applied voltage,
VR{V_R} represents the rms voltage measured across the resistor RR ,
VL{V_L} represents the rms voltage measured across the inductor LL , and
VC{V_C} represents the rms voltage measured across the capacitor CC
Now we substitute the values of VR{V_R} , VL{V_L} and VC{V_C} in the above equation.
We get,
Vnet=(20)2+(10085)2 =(20)2+(15)2 =400+225 =625 =25  {V_{net}} = \sqrt {{{\left( {20} \right)}^2} + {{\left( {100 - 85} \right)}^2}} \\\ = \sqrt {{{\left( {20} \right)}^2} + {{\left( {15} \right)}^2}} \\\ = \sqrt {400 + 225} \\\ = \sqrt {625} \\\ = 25 \\\
We found that Vnet=25V{V_{net}} = 25V
Therefore, the magnitude of the applied voltage is equal to 2525 volts.

Additional Information:
The highest voltage mentioned in electricity transmission is 1200KV1200KV . China currently uses the maximum voltage of 800KV800KV and is working on a 1100KV1100KV system. In the first step, Powergrid will construct a 380380 kilometer 12001200 volt transmission line from Deoli to Aurangabad.
Note :
It's not a smart idea to plug a 220V220V unit into a 110V110V socket. If you did, the appliance is most likely to be damaged or destroyed. If your system lacks a motor, it will operate poorly, using half the energy used. If the system has a motor, the lower voltage will cause it to malfunction.