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Question

Question: In the circuit shown in figure, if the diode forward voltage drop is \(0.3V,\) the voltage differenc...

In the circuit shown in figure, if the diode forward voltage drop is 0.3V,0.3V, the voltage difference between A and B is

A

1.3V1.3V

B

2.3V2.3V

C

0

D

0.5V0.5V

Answer

2.3V2.3V

Explanation

Solution

: Let V be the potential difference between A and B, then

V0.3=(5+5)×103×(0.2×103)=2V - 0.3 = (5 + 5) \times 10^{3} \times (0.2 \times 10^{- 3}) = 2

Or V=2+0.3=2.3VV = 2 + 0.3 = 2.3V