Question

In the circuit shown in figure, if the diode forward voltage drop is $0.3V,$ the voltage difference between A and B is

• A. $1.3V$
• B. $2.3V$
• C. 0
• D. $0.5V$

Answer 1

Answer: (B)

$2.3V$

Answer 2

: Let V be the potential difference between A and B, then

$V - 0.3 = (5 + 5) \times 10^{3} \times (0.2 \times 10^{- 3}) = 2$

Or $V = 2 + 0.3 = 2.3V$