Question

In the circuit shown below, the power developed in the 6Ω resistor is 6 watt. The power in watts developed in the 4Ω resistor is

• A. 16
• B. 9
• C. 6
• D. 4

Answer 1

Answer: (B)

9

Answer 2

$P = \frac{V^{2}}{R}$ ⇒ $\frac{P_{1}}{P_{2}} = \frac{R_{2}}{R_{1}}$⇒ $\frac{6}{P_{2}} = \frac{4}{6} = \frac{2}{3}$ ⇒ $P_{2} = 9W$