Question

In the circuit shown below, maximum Zener diode current will be ________ mA.

Answer 1

$i_s=\frac {60}{4×10^3}$

$i_s=15×10^{−3}$

$i_s=15\ mA$

$i_L=\frac {60}{10×10^3}$

$i_L=6\ mA$
The maximum Zener diode current,
$I_z=i_s–i_L$
$I_z = 15 mA - 6 mA$
$I_z=9 mA$

So, the answer is $9\ mA$.