Question

In the circuit shown below, if the resistance of voltmeter is 4 kW, then the error in the reading of voltmeter will be –

• A. 50 %
• B. 68 %
• C. 17 %
• D. 33.3 %

Answer 1

Answer: (D)

33.3 %

Answer 2

(i) Without using voltmeter

V_4kW = 2 volt

(ii) With voltmeter

R_AB = 2kW Þ V_AB = $\frac{1}{3}$× 4 = $\frac{4}{3}$volt

Þ % error = $\frac{2 - 4/3}{2}$×100 = $\frac{200}{6}$ = $\frac{100}{3}$=33.3%