Question
Question: In the circuit shown below, calculate the net resistance of the circuit. R2 connected in series, then their net resistance can be calculated as Rseries=R1+R2 whereas when these two same resistors are connected in parallel combination then, we can calculate their net resistance as Rparallel1=R11+R21.
Complete step by step answer:
Let us first find the net resistance among the series combination of resistances 10Ω(and)15Ω let’s say net resistance among this series combination is R10,15 now, using series formula Rseries=R1+R2 we have,
R10,15=10+15
⇒R10,15=25Ω→(i)
Now, again we have resistances of 20Ω(and)5Ω are connected in series so using again series formula Rseries=R1+R2 , their net resistance can be written as,
R20,5=20+5
⇒R20,5=25Ω→(ii)
Now, the net resistances of R10,15(and)R20,5 both are connected in parallel combination, so using parallel combination formula Rparallel1=R11+R21 we can find net resistance of circuits as:
Rnet1=R10,151+R20,51
Put the values from the equations R10,15=25Ω→(i) and R20,5=25Ω→(ii) we have,
Rnet1=251+251
⇒Rnet1=252
∴Rnet=12.5Ω
Hence, the net resistance of the given circuit diagram is Rnet=12.5Ω.
Note: It should be remembered that, when two resistances are connected in series combination, the current flowing across both resistances are same but potential difference is different. while in parallel combination, the potential difference across both resistances is same but different current flows across both the resistances.