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Question

Physics Question on Current electricity

In the circuit shown, a four-wire potentiometer is made of a 400cm400\, cm long wire, which extends between AA and BB. The resistance per unit length of the potentiometer wire is r=0.01r = 0.01 Ω/cm\Omega/cm. If an ideal voltmeter is connected as shown with jockey JJ at 50cm50\, cm from end AA, the expected reading of the voltmeter will be :

A

0.20 V

B

0.25 V

C

0.75 V

D

0.50V

Answer

0.25 V

Explanation

Solution

Resistance of wire AB=400×0.01=4ΩAB = 400 \times 0.01 = 4 \Omega
i=36=0.5Ai = \frac{3}{6} = 0.5 A
Now voltmeter reading = ii (Resistance of 50 cm length)
=(0.5A)(0.01×50)=0.25= (0.5 A) (0.01 \times 50) = 0.25 volt