Question

In the circuit of following figure, the final voltage drop across the capacitor C in steady state –

• A. $\frac{Vr_{1}}{r_{1} + r_{2}}$
• B. $\frac{Vr_{2}}{r_{1} + r_{2}}$
• C. $\frac{V(r_{1} + r_{2})}{r_{2}}$
• D. $\frac{V(r_{2} + r_{1})}{r_{1} + r_{2} + r_{3}}$

Answer 1

Answer: (B)

$\frac{Vr_{2}}{r_{1} + r_{2}}$

Answer 2

In steady state, the capacitor arm presents an infinite resistance. So the potential difference across C is that across r₂.

Current through r₂ = $\frac{V}{r_{1} + r_{2}}$

P.D. across r₂ = $\frac{Vr_{2}}{r_{1} + r_{2}}$