Question
Question: In the circuit given, the current through the zener diode is. <img src="https://cdn.pureessence.tec...
In the circuit given, the current through the zener diode is.

A
10 mA
B
6.67 Ma
C
5 mA
D
3.33 mA
Answer
3.33 mA
Explanation
Solution
:

The voltage drop across R2is
VR2=VZ=10V
The current through R2is
IR2=R2VR2=1500Ω10V=0.667×10−2A
The voltage drop across R1is ()
}{= 15V - 10V = 5V}$$ The current through $R_{1}$is $$I_{R_{1}} = \frac{V_{R_{1}}}{R_{1}} = \frac{5V}{500\Omega} = 10^{- 2}A = 10 \times 10^{- 3}A = 10mA$$ The current through the zener diode is $${I_{Z} = I_{R_{1}} - I_{R_{2}} }{= (10 - 6.67)mA = 3.33mA}$$