Question

In the circuit diagram shown in the adjoining figure, the resultant capacitance between P and Q is

• A. $47\mu F$
• B. $3\mu F$
• C. $60\mu F$
• D. $10\mu F$

Answer 1

Answer: (B)

$3\mu F$

Answer 2

The given circuit can be drawn as

where $C = (3 + 2)\mu F = 5\mu F$

$\frac{1}{C_{PQ}} = \frac{1}{5} + \frac{1}{20} + \frac{1}{12} = \frac{20}{60} = \frac{1}{3}$

⇒ $C_{PQ} = 3\mu F$