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Chemistry Question on Chemical bonding and molecular structure

In the change of NO → NO+NO \, \to\, NO^+ the electron is added to

A

σ\sigma - orbital

B

π\pi - orbital

C

σ∗\sigma^* - orbital

D

π∗\pi^* - orbital

Answer

π∗\pi^* - orbital

Explanation

Solution

M.O. configuration of NO+NO ^{+}is
σ1s2,σ∗1s2,σ2s2,σ∗2s2,π2px2≈π2py2,π2pz2\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \pi 2 p_{z}^{2}
and M.O. configuration of NONO is
σ1s2,σ∗1s2,σ2s2,σ∗2s2,π2px2≈π2py2,π∗2px1\sigma 1 s^{2}, \sigma^{*} 1 s^{2}, \sigma 2 s^{2}, \sigma^{*} 2 s^{2}, \pi 2 p_{x}^{2} \approx \pi 2 p_{y}^{2}, \pi^{*} 2 p_{x}^{1}