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Question: In the case of sound waves, wind is blowing from source to receiver with speed U<sub>w</sub>. Both t...

In the case of sound waves, wind is blowing from source to receiver with speed Uw. Both the source and the receiver are stationary. If λ0is the original wavelength with no wind and V is speed of sound in air then the wavelength as received by the receiver is given by:

A

λ0

B

(V+UwV)λ0\left( \frac{V + U_{w}}{V} \right)\lambda_{0}

C

(VUwV)λ0\left( \frac{V - U_{w}}{V} \right)\lambda_{0}

D

(VV+Uw)λ0\left( \frac{V}{V + U_{w}} \right)\lambda_{0}

Answer

(V+UwV)λ0\left( \frac{V + U_{w}}{V} \right)\lambda_{0}

Explanation

Solution

If f0 is frequency of source then in ∆t time, it sends N = f0t waves. These are now contained in distance (V + Uw)∆t.

Thus λ' = (V+Uw)Δtf0Δt\frac{\left( V + U_{w} \right)\Delta t}{f_{0}\Delta t}

(V+Uw)f0=(V+Uw)Vλ0\frac{\left( V + U_{w} \right)}{f_{0}} = \frac{\left( V + U_{w} \right)}{V}\lambda_{0}