Question

In the Bohr's hydrogen atom model, the radius of the stationary orbit is directly proportional to (n = principle quantum number).

• A. $\beta$
• B. n
• C. $n^{- 2}$
• D. $n^{2}$

Answer 1

Answer: (D)

$n^{2}$

Answer 2

Bohr radius $r = \frac{\varepsilon_{0}n^{2}h^{2}}{\pi Zme^{2}};\mspace{6mu}\mspace{6mu}\therefore r \propto n^{2}$ .