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Question: In the binomial (2<sup>1/3</sup> + 3<sup>–1/3</sup>) <sup>n</sup>, if the ratio of the seventh term ...

In the binomial (21/3 + 3–1/3) n, if the ratio of the seventh term from the beginning of the expansion to the seventh term from its end is 1/6 then n =

A

6

B

9

C

12

D

15

Answer

9

Explanation

Solution

Tr + 1 = nCr an–r . br where a = 21/3 and b = 3–1/3

T7 from beginning = nC6 an–6 b6 and T7 from end = nC6 bn–6 a6 Ž an12bn12\frac{a^{n–12}}{b^{n–12}}= 16\frac{1}{6}

Ž 2n123.3n1232^{\frac{n–12}{3}}.3^{\frac{n–12}{3}} = 6–1

Ž n – 12 = – 3

Ž n = 9