Question

In the arrangement shown in figure a 1, a 2, a 3 and a 4 are the accelerations of masses m 1, m 2, m 3 and m 4 respectively. Which of the following relation is true for this arrangement

Fig.

• A. 4 a 1 + 2 a 2 + a 3 + a 4 = 0
• B. a 1 + 4 a 2 + 3 a 3 + a 4 = 0
• C. a 1 + 4 a 2 + 3 a 3 + 2 a 4 = 0
• D. 2 a 1 + 2 a 2 + 3 a 3 + a 4 = 0

Answer 1

Answer: (A)

4 a 1 + 2 a 2 + a 3 + a 4 = 0

Answer 2

The correct answer is (A) : $4a_1 \+ 2a_2 + a_3 + a_4 = 0$
From virtual work done method,
$4T \times a_1 \+ 2T \times a_2 + T \times a_3 + T \times a_4 = 0$
$\Rightarrow 4a_1 \+ 2a_2 + a_3 + a_4 = 0$