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Question

Question: In the arrangement shown in Fig. pulleys are smooth and massless. Threads are massless and inextensi...

In the arrangement shown in Fig. pulleys are smooth and massless. Threads are massless and inextensible. Find acceleration of mass m1.

A

[2m1m2+m0(m1m2)]g2m1m2+m0(m1+m2)\frac { \left[ 2 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } - m _ { 2 } \right) \right] g } { 2 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } + m _ { 2 } \right) }

B

[4m1m2+m0(m1m2)]g4m1m2+m0(m1+m2)\frac { \left[ 4 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } - m _ { 2 } \right) \right] g } { 4 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } + m _ { 2 } \right) }

C

[4m1m2m0(m1m2)]g4m1m2+m0(m1+m2)\frac { \left[ 4 m _ { 1 } m _ { 2 } - m _ { 0 } \left( m _ { 1 } - m _ { 2 } \right) \right] g } { 4 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } + m _ { 2 } \right) }

D

None of these

Answer

[4m1m2+m0(m1m2)]g4m1m2+m0(m1+m2)\frac { \left[ 4 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } - m _ { 2 } \right) \right] g } { 4 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } + m _ { 2 } \right) }

Explanation

Solution

m1g – T = m1a1 [from Fig. (ii)]

m2g – T = m2a2 [from Fig. (iii)]

m0a = 2T [from Fig. (i)]

Solving we get a1 = [4m1m2+m0(m1m2)]g4m1m2+m0(m1+m2)\frac { \left[ 4 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } - m _ { 2 } \right) \right] g } { 4 m _ { 1 } m _ { 2 } + m _ { 0 } \left( m _ { 1 } + m _ { 2 } \right) }