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Question: In the arrangement shown, by what acceleration the boy must go up so that 100 kg block remains stati...

In the arrangement shown, by what acceleration the boy must go up so that 100 kg block remains stationary on the wedge? The wedge is fixed and friction is absent everywhere. (Take g = 10 m/s2)

A

3 m/s2

B

5 m/s2

C

6 m/s2

D

8 m/s2

Answer

6 m/s2

Explanation

Solution

For block to be stationary

T = 800 N

If the boy moves up by an acceleration a in upward direction then mg = 500 N

T – mg = ma

800-500 = 50 a

a = 6 m/s2.

For block to be stationary \nT=800 N\n\nT = 800 \mathrm {~N}\n If the boy moves up by an acceleration a in upward direction then T−mg=ma800−500=50aa=6 m/s2\begin{array} { l } T - \mathrm { mg } = \mathrm { ma } \\ 800 - 500 = 50 \mathrm { a } \\ \mathrm { a } = 6 \mathrm {~m} / \mathrm { s } ^ { 2 } \end{array}