Solveeit Logo

Question

Question: In the adjacent diagram, CP represents a wave front and AO and BP. The corresponding two rays. Find ...

In the adjacent diagram, CP represents a wave front and AO and BP. The corresponding two rays. Find the condition on θ\theta for constructive interference at P between the ray BP and the reflected ray OP.

Explanation

Solution

For the constructive interference to take place, the path difference between two interfering waves should be half integral multiple of the wavelength of the light. Using the given diagram and rules of trigonometry, we can derive the required condition on θ\theta for constructive interference at P between the ray BP and the reflected ray OP.

Complete answer:
We are given a wave front CP. The ray AO is incident on a reflecting surface QR and the reflected ray OP meets the ray BP at point P. We need to find the condition on θ\theta for constructive interference at P between the ray BP and the reflected ray OP.
From the diagram, we can find the following relations between various lengths.
OP=dsecθOP = d\sec \theta
In the triangle COP, CO=POcos2θCO = PO\cos 2\theta
Inserting the value of OP, we get CO=dsecθcos2θCO = d\sec \theta \cos 2\theta
Now we can write the path difference between the two rays of the wave front in the following way.
Δ=CO+PO=dsecθ+dsecθcos2θ\Delta = CO + PO = d\sec \theta + d\sec \theta \cos 2\theta
In order to obtain the constructive interference, the value of path difference should be
Δ=λ2,3λ2,5λ2,...\Delta = \dfrac{\lambda }{2},\dfrac{{3\lambda }}{2},\dfrac{{5\lambda }}{2},...
For the first order maximum, we can write
dsecθ+dsecθcos2θ=λ2 dsecθ(1+cos2θ)=λ2 dsecθ×2cos2θ=λ2 2dcosθ=λ2 θ=cos1(λ4d)  \Rightarrow d\sec \theta + d\sec \theta \cos 2\theta = \dfrac{\lambda }{2} \\\ \Rightarrow d\sec \theta \left( {1 + \cos 2\theta } \right) = \dfrac{\lambda }{2} \\\ \Rightarrow d\sec \theta \times 2{\cos ^2}\theta = \dfrac{\lambda }{2} \\\ \Rightarrow 2d\cos \theta = \dfrac{\lambda }{2} \\\ \Rightarrow \theta = {\cos ^{ - 1}}\left( {\dfrac{\lambda }{{4d}}} \right) \\\
This is the required condition on θ\theta for constructive interference at P between the ray BP and the reflected ray OP.

Note:
The given diagram helps us understand how we can obtain the interference from a single wave front. The reflection allows us to change the path of the light wave. The reflected waves interfere with the original wave from the wave front and give us an interference pattern. The angle that we have obtained is the value of theta at which we will obtain constructive interference at point P where the original ray and the reflected ray meet.