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Question: In the above que., the rate of change of potential difference between the plates is:...

In the above que., the rate of change of potential difference between the plates is:

A

2.41×109Vs−12.41 \times 10^{9}Vs^{- 1}

B

1.87×109Vs−11.87 \times 10^{9}Vs^{- 1}

C

3.2×109Vs−13.2 \times 10^{9}Vs^{- 1}

D

4.5×10−4Vs−14.5 \times 10^{- 4}Vs^{- 1}

Answer

1.87×109Vs−11.87 \times 10^{9}Vs^{- 1}

Explanation

Solution

: Here, C=80×10−12FC = 80 \times 10^{- 12}F

I=0.15AI = 0.15A

Also q = CV

or dqdt=C×dVdt\frac{dq}{dt} = C \times \frac{dV}{dt}

i.e I=CdVdtI = C\frac{dV}{dt}

or dVdt=IC=0.1580×10−12\frac{dV}{dt} = \frac{I}{C} = \frac{0.15}{80 \times 10^{- 12}}

=1.87×109Vs−1= 1.87 \times 10^{9}Vs^{- 1}