Question
Question: In terms of potential difference V, electric current I, permittivity \({\varepsilon _{\text{o}}}\), ...
In terms of potential difference V, electric current I, permittivity εo, permeability μo and speed of light c, the dimensionally correct equation(s) is/are:
(This question has multiple correct options)
A. μoI2=εoV2 B. μoI=εoV C. I=εocV D. μocI=εoV
Solution
- Hint: In order to find all the dimensionally correct options we check each individual option separately by using the formulae of speed of light c, resistance R in terms of permittivity and permeability and Ohm’s law.
Ohm’s law: V = IR
Formula Used,
C = μoεo1
R = εoμo
Ohm’s Law – V = IR
Complete step-by-step solution :
We could check if all the options are dimensionally correct or not by two methods. We could use their formulae to verify or we could write down the units of each quantity and verify.
We use the formulae of speed of light C and resistance R in terms of μo and εo, to find the answer.
The speed of light C is given as C = μoεo1
The resistance can be expressed as R = εoμo
And we know, V = IR, where V, I, R are the voltage, current and resistance respectively.
μoI2=εoV2
⇒εoμo= (IV)2
⇒εoμo= (R)2
⇒εoμo= (εoμo) - - - - - Since R = εoμo
Option A is correct.
μoI=εoV
⇒εoμo=IV ⇒εoμo=R ⇒εoμo=εoμo
Option B is not correct.
I=εocV
⇒VI=εoεoμo1 ⇒R1=μoεo ⇒μoεo=μoεo
Option C is correct.
μocI=εoV
⇒εoμoεoμo1=IV ⇒εoμo=Rεo
Option D is not correct.
Options A and C are the correct options.
Note – In order to answer this type of question the key is to know to express the given equation in terms of one another. We can also solve this question by only verifying the options using the units of given variables in the question.
The dimensions of the terms given are –
[V] = [M−1L2T−3A−1] [I] = [A] [c] = [L1T−1] [εo] = [M−1L−3T4A2] [μo] = [M1L1T−2A−2]
These dimensions can be performed in each option to verify them, we should still get the same answer.