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Question: In terms of mechanical units, \({C_p} - {C_v} = \cdots \) where \({C_p}\) and \({C_v}\) are principa...

In terms of mechanical units, CpCv={C_p} - {C_v} = \cdots where Cp{C_p} and Cv{C_v} are principal specific heats.
A) 2R2R
B) RM\dfrac{R}{M}
C) RJ\dfrac{R}{J}
D) RM\dfrac{R}{{M}}

Explanation

Solution

Cp{C_p} is molar specific heat at constant pressure and Cv{C_v} is molar specific heat at constant volume. Use mayor’s relation for specific heat and specific heat capacity. One is for 1 mole and the other is for 1gm.

Complete step by step solution:
The relation given by Robert Mayer between Cp{C_p} and Cv{C_v} is –
CpCv=R{C_p} - {C_v} = R eq(1) \cdots eq(1)
Here in eq(1) \cdots eq(1) the relation is in between molar specific heats but we have to find out the relation between principal specific heats in terms of mechanical unit
So the relation mechanical unit (Joule) is –
CpCv=RJ{C_p} - {C_v} = \dfrac{R}{J} eq(2) \cdots eq(2)
Where JJ is used for unit conversion of RR from calories to joule, because Cp{C_p} and Cv{C_v} are given in joule, in mechanical units and RR was in calories.

Hence, option (C)\left( C \right) is the correct choice.

Note: If one of Cp{C_p} or Cv{C_v} are given in joule and other one in question is expecting to find out then we are going to use eq(2) \cdots eq(2) because here RR is joule and we will get answer in joule. And for calorie we have to use eq(1) \cdots eq(1).