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Question

Chemistry Question on Nucleic Acids

In terms of energy 11 amu is equal to:

A

100 J

B

931.1 kcal

C

931.1 MeV

D

107erg10^{7}erg

Answer

931.1 MeV

Explanation

Solution

1 amu=1.67×10−24g1\, amu =1.67 \times 10^{-24} g Energy equivalent to this mass can be calculated by using the relation; E=mc2E =m c^{2} Here m=1.67×10−24gm =1.67 \times 10^{-24} g c=3×1010cm sec⁡−1c=3 \times 10^{10} cm\, \sec ^{-1} ∴E=1.67×10−24×(3×1010)2\therefore E =1.67 \times 10^{-24} \times\left(3 \times 10^{10}\right)^{2} ergs =1.503×10−3107J=\frac{1.503 \times 10^{-3}}{10^{7}} J =1.503×10−10J=1.503 \times 10^{-10} J Now, 1.6×10−19J=1 eV1.6 \times 10^{-19} J =1\, eV 1 J=11.6×10−19eV1\, J =\frac{1}{1.6 \times 10^{-19}} eV =6.25×1018eV=6.25 \times 10^{18} eV ∴1.503×10−10J\therefore 1.503 \times 10^{-10} J =6.25×1018×1.503×10−10eV=6.25 \times 10^{18} \times 1.503 \times 10^{-10} eV =9.393×108eV=9.393 \times 10^{8} eV ∴1 amu=939.3 MeV\therefore 1\, amu =939.3\, MeV