Question
Physics Question on Dimensional Analysis
In terms of basic units of mass (M), length (L), time (T) and charge (Q), the dimensions of magnetic permeability of vacuum (μ0) would be
A
[MLQ−2]
B
[LT−1Q−1]
C
[ML2T−1Q−2]
D
[LTQ−1]
Answer
[MLQ−2]
Explanation
Solution
The force per unit length experienced due to two wires in which current is flowing in the same direction is given by dldF=4πμ0d2I1I2 ⇒[L][MLT−2]=[μ0][L][A2] ⇒[L][MLT−2]=μ0[T2LO2] ⇒μ0=[MLQ−2]