Solveeit Logo
Login

Question

Question: In steel, the Young’s modulus and the strain at the breaking point are \(2 \times 10^{11}Nm^{- 2}\) ...

In steel, the Young’s modulus and the strain at the breaking point are 2×1011Nm−22 \times 10^{11}Nm^{- 2} and 0.15 respectively. The stress at the breaking point for steel is therefore

A

1.33×1011Nm−21.33 \times 10^{11}Nm^{- 2}

B

1.33×1012Nm−21.33 \times 10^{12}Nm^{- 2}

C

7.5×10−13Nm−27.5 \times 10^{- 13}Nm^{- 2}

D

3×1010Nm−23 \times 10^{10}Nm^{- 2}

Answer

3×1010Nm−23 \times 10^{10}Nm^{- 2}

Explanation

Solution

Y=StressStrainY = \frac{\text{Stress}}{\text{Strain}} ∴\thereforeStress = Y × Strain =2×1011×0.15=0.3×1011=3×1010N/m2= 2 \times 10^{11} \times 0.15 = 0.3 \times 10^{11} = 3 \times 10^{10}N/m^{2}