Question

In sine wave, minimum distance between $2$ particles always having same speed is

• A. $\frac{\lambda}{2}$
• B. $\frac{\lambda}{4}$
• C. $\frac{\lambda}{3}$
• D. $\lambda$

Answer 1

Answer: (A)

$\frac{\lambda}{2}$

Answer 2

Sine wave

Particle velocity $v_{p}=\frac{d y}{d t}=$ slope of wave at that point.
As slope at $A$ and $B$ is zero. Hence the velocity at $A$ and $B$ will be same. Distance between $A$ and $B$ is $\frac{\lambda}{2}$.