Question

In shooting competition, a person hits the target 3 out of 4 times. Find out the probability that he will hit the target.
a) $\dfrac{1}{4}$
b) $\dfrac{1}{2}$
c) $\dfrac{3}{4}$
d) $\dfrac{3}{7}$

Answer 1

Hint: We know that probability of anything is given by formula $P\left( E \right)=\dfrac{\text{favoured outcome}}{\text{total outcome possible}}$ here the favoured outcome means which is our required possibility and total outcome means all possible outcome. Here we have total outcomes as 4, now try to get the favoured outcome by understanding the question.

Complete step-by-step answer:
It is given in the question that in a shooting competition, a person hits the target 3 out of 4 times, then we have to find the probability that he will hit the target.
We know that the probability of any event/ thing happening is given by the formula $P\left( E \right)=\dfrac{\text{favoured outcome}}{\text{total outcome possible}}$ here the favoured outcome means which is our required possibility and total outcome means all possible outcome.
Like tossing a coin has two outcomes, either head or tail and the probability that either it is head and it is tail is equal to $\dfrac{1}{2}$.
Similarly, in the given question, the shooter shoots 4 times, so $total\text{ }possibility~=\text{ }4$.
Out of 4 times, 3 hit the target, so $favoured\text{ }outcome\text{ }=\text{ }3$.
Therefore, the probability that he will hit the target is $P\left( E \right)=\dfrac{\text{favoured outcome}}{\text{total outcome possible}}=\dfrac{3}{4}$.
Thus, option c) is the correct answer of this question.

Note: This is a very basic question of probability but many times students miss-read this question that he will miss the target instead of hit the target which will change the meaning of the question and further completely reverse the answer. Thus, it is recommended to read the question carefully before solving it.