Question

In series LCR circuit voltage drop across resistance is 8 volt and across capacitor is 12 volt. Then :

• A. Voltage of the source will be leading current in the circuit
• B. Voltage drop across each element will be less than the applied voltage
• C. Power factor of circuit will be 4/3
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

Since, cosq = $\frac{R}{Z}$ = $\frac{IR}{IZ}$ = $\frac{8}{10}$ = $\frac{4}{5}$

(cosq can never be greater than 1)

Also, Ix_C > Ix_L Ž X_C > X_L

Current will be leading

In a LCR circuit

$V = \sqrt{(V_{L}–V_{C})^{2}}$ $= \sqrt{(6–12)^{2} + 8^{2}}$

V = 10 ; which is less than voltage drop across capacitor .