Solveeit Logo
Login

Question

Question: In series LCR circuit, the plot of \(l_{m}\)vs \(\omega\)is shown in the figure. The bandwidth of th...

In series LCR circuit, the plot of lml_{m}vs ω\omegais shown in the figure. The bandwidth of this plot will be

A

Zero

B

0.1rads−1s^{- 1}

C

0.2rads−1s^{- 1}

D

0.4rads−1s^{- 1}

Answer

0.4rads−1s^{- 1}

Explanation

Solution

: Bandwidth is the frequency range at which current amplitude

Im=12Imax⁡max⁡I_{m} = \frac{1}{\sqrt{2}}{I\max}_{\max}

From figure,

Band width, Δω=1.2−0.8=0.4rads−1\Delta\omega = 1.2 - 0.8 = 0.4rads^{- 1}