Question

In Rutherford scattering experiment, the number of a-particles scattered at 60° is 5 × 10⁶. The number of a-particles scattered at 120° will be-

• A. 15 × 10⁶
• B. $\frac{3}{5}$× 10⁶
• C. $\frac{5}{9}$ × 10⁶
• D. None

Answer 1

Answer: (C)

$\frac{5}{9}$ × 10⁶

Answer 2

N µ $\frac{1}{\sin^{4}\theta/2}$