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Question: In reaction 3A \(\longrightarrow\)2B. Concentration of product increases from \(\frac{2mol}{lit}\)to...

In reaction 3A ⟶\longrightarrow2B. Concentration of product increases from 2mollit\frac{2mol}{lit}to 10moleslit\frac{10moles}{lit}in 5 min. calculates rate of reaction -

A

85\frac { 8 } { 5 } mollit–sec⁡\frac{mol}{lit–\sec}

B

85\frac { 8 } { 5 } mollit–min⁡\frac{mol}{lit–\min}

C

58\frac { 5 } { 8 } mollit–sec⁡\frac{mol}{lit–\sec}

D

58\frac { 5 } { 8 } mollit–min⁡\frac{mol}{lit–\min}

Answer

\frac { 8 } { 5 }$$\frac{mol}{lit–\min}

Explanation

Solution

R = RB2\frac{R_{B}}{2} Ž RB = +Δ[B]Δt\frac{\Delta\lbrack B\rbrack}{\Delta t} = (10–2)5\frac{(10–2)}{5}