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Question

Physics Question on Ray optics and optical instruments

In Ramsden eye-piece the focal length of each lens is FF . The distance of the image formed by the objective lens from the eye lens is

A

14F15\frac{14F}{15}

B

13F14\frac{13F}{14}

C

12F13\frac{12F}{13}

D

11F12\frac{11F}{12}

Answer

11F12\frac{11F}{12}

Explanation

Solution

The distance of image fanned by the objective lens from the eye lens =2F3+F4=8F+3F12=11F12=\frac{2F}{3}+ \frac{F}{4}=\frac{8F\, +\, 3F}{12}=\frac{11F}{12}