Solveeit Logo
Login

Question

Question: In pure semiconductor, the number of conduction electrons is \(6 \times 10^{18}\) per cubic metre. H...

In pure semiconductor, the number of conduction electrons is 6×10186 \times 10^{18} per cubic metre. How many holes are there in a sample of size 1cm×1cm×11cm \times 1cm \times 1 mm?

A

3×10103 \times 10^{10}

B

6×10116 \times 10^{11}

C

3×10113 \times 10^{11}

D

6×10106 \times 10^{10}

Answer

6×10116 \times 10^{11}

Explanation

Solution

: here, ne=6×1018m−3n_{e} = 6 \times 10^{18}m^{- 3}

Volume of the sample

=1cm×1cm×1mm=10−7m3= 1cm \times 1cm \times 1mm = 10^{- 7}m^{3}

Number of holes in the sample=

Number of electrons in the sample

}{= 6 \times 10^{18} \times 10^{- 7} }{6 \times 10^{11}}$$