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Question: In presence of air, fermentation of ethyl alcohol by azotobactor bacteria forms...

In presence of air, fermentation of ethyl alcohol by azotobactor bacteria forms

A

CH2=CH2\mathrm { CH } _ { 2 } = \mathrm { CH } _ { 2 }

B

C2H6\mathrm { C } _ { 2 } \mathrm { H } _ { 6 }

C

CH3CHO\mathrm { CH } _ { 3 } \mathrm { CHO }

D

CH3COOH\mathrm { CH } _ { 3 } \mathrm { COOH }

Answer

CH3COOH\mathrm { CH } _ { 3 } \mathrm { COOH }

Explanation

Solution

C2H5OH Acetobacto racetii  air CH3COOH\mathrm { C } _ { 2 } \mathrm { H } _ { 5 } \mathrm { OH } \xrightarrow [ \text { Acetobacto racetii } ] { \text { air } } \mathrm { CH } _ { 3 } \mathrm { COOH }