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Question

Chemistry Question on Chemical bonding and molecular structure

In PO43PO_{4}^{3-} ion, the formal charge on each oxygen atom and POP-O bond order respectively are :

A

-0.75, 1.25

B

-0.75, 1.0

C

-0.75, 0.6

D

-3.1, 25

Answer

-0.75, 1.25

Explanation

Solution

Average formal charge on each of the oxygen atom rs calculated as follows :
(i) Total number of electrons present in valence shell of (P0)=5+8=13(P-0)=5+8=13
(ii) Total number of electrons involved in bond formation =133=10=13-3=10
(iii) Number of bonds in PO43P O_{4}^{3-} ion =102=5=\frac{10}{2}=5
(iv) Average P-0 bond order =54=1.25=\frac{5}{4}=1.25
(v) Average formal charge on each 'O' atom
= total charge  total entity of O atom =\frac{\text { total charge }}{\text { total entity of }^{\prime} O^{\prime} \text { atom }}
=34=0.75=-\frac{3}{4}=-0.75