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Question: In order to raise a mass of 100 kg a man of mass 60 kg fastens a rope to it and passes the rope over...

In order to raise a mass of 100 kg a man of mass 60 kg fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration 5g/4 relative to the rope. The tension in the rope is : (g = 10 m/s2)

A

1432 N

B

928 N

C

1218 N

D

642 N

Answer

1218 N

Explanation

Solution

If 'a' is the acceleration of body w.r.t. ground then acceleration of man w.r.t. ground = 54g−a\frac{5}{4}g - a

Thus for body,

T – 100 g = 100 a ....(i)

for man, T – 60 g = 60(54g−a)60\left( \frac{5}{4}g - a \right)

 T = 135 g – 60 a ....(ii)

By solving eq. (i) and (ii)

T = 1218 N