Question

In order to pass 10% of main current through a moving coil galvanometer of 99 ohm, the resistance of the required shunt is

• A. $9.9\Omega$
• B. $10\Omega$
• C. $11\Omega$
• D. $9\Omega$

Answer 1

Answer: (C)

$11\Omega$

Answer 2

Shunt resistances

$S = \frac{i_{g}G}{(i - i_{g})} = \frac{10 \times 99}{(100 - 10)} = 11\Omega$