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Question

Physics Question on Alternating current

In order to obtain time constant of 10s10\, s in an RCR-C circuit containing a resistance of 103Ω10^3 \Omega , the capacity of the condenser should be

A

$10, \mu,F

B

$100, \mu,F

C

$1000 ,\mu,F

D

$10000 ,\mu,F

Answer

$10000 ,\mu,F

Explanation

Solution

In an RCR - C circuit, the product τc=CR\tau_{c}= CR is the capacitive time constant of the circuit.
Given, τc=10s,R=103Ω\tau_{c}=10 s, R=10^{3} \Omega
C=τcR=10103=102F\therefore C=\frac{\tau_{c}}{R}=\frac{10}{10^{3}}=10^{-2} F
C=10000μF\Rightarrow C=10000\, \mu F