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Question

Physics Question on physical world

In order to measure the period of a single pendulum using a stop clock, a student repeated the experiment for 1010 times and noted down the time period for each experiment as 5.1,5.0,4.9,4.9,5.1,5.0,4.9,5.1,5.0,4.9s5.1, 5.0, 4.9, 4.9, 5.1, 5.0, 4.9, 5.1, 5.0, 4.9\, s . The correct way of expressing the result for the period is

A

4.99 s

B

5.0 s

C

5.00s

D

4.9 s

Answer

5.0 s

Explanation

Solution

Mean =Σxifi10=(4.9×4)+(5.0×3)+(5.1×3)10=\frac{\Sigma x_{i} f_{i}}{10}=\frac{(4.9 \times 4)+(5.0 \times 3)+(5.1 \times 3)}{10}
=4.99s=4.99 \,s
Which can be round off to 5.0s5.0\, s correct to two significant figures.