Solveeit Logo
Login

Question

Question: In order to establish an instantaneous displacement current of 1mA in the space between the plates o...

In order to establish an instantaneous displacement current of 1mA in the space between the plates of 2μF\mu Fparallel plate capacitor, the potential difference need to apply is:

A

100Vs−1- 1

B

200Vs−1200Vs^{- 1}

C

300Vs−1300Vs^{- 1}

D

500Vs−1500Vs^{- 1}

Answer

500Vs−1500Vs^{- 1}

Explanation

Solution

: ID=1mA=10−3AI_{D} = 1mA = 10^{- 3}A

C=2μF=2×10−6FC = 2\mu F = 2 \times 10^{- 6}F

ID=IC=ddt(CV)=CdVdtI_{D} = I_{C} = \frac{d}{dt}(CV) = C\frac{dV}{dt}

Therefore, dVdt=IDC=10−32×10−6=500Vs−1\frac{dV}{dt} = \frac{I_{D}}{C} = \frac{10^{- 3}}{2 \times 10^{- 6}} = 500Vs^{- 1}

Therefore, applying a varying potential difference of 500Vs−1500Vs^{- 1} would produce a displacement current of desired value.