Question

In n- p-n transistor, the collector current is 10 mA. If 90% of the electrons emitted reach the collector, then

• A. emitter current will be 9 mA
• B. emitter current will be 11.1 mA
• C. base current will be 0.1 mA,
• D. base current will be 0.01 mA

Answer 1

Answer: (B)

emitter current will be 11.1 mA

Answer 2

Collector current $I_C =10 \,mA$
Given, $I_C =\frac{90}{100}I_E$
$\therefore I_E =\frac{100}{90} \times 10$
$=\frac{100}{9} mA$
Also, $I_B=I_E -I_C =11.1 \,mA =11.1 -10 =1.1\, mA$